export = in declarations file

[fdecampredon]

I try to use bluebird.
The definition file is like that.

declare module "bluebird" {

  declare class Promise<R>  {
    constructor(callback: (resolve : (result: R) => void, reject: (error: any) => void) => void): void;
    then<U>(onFulfill?: (value: R) => Promise<U> | U, onReject?: (error: any) => Promise<U> | U): Promise<U>;
    catch<U>(onRejected?: (error: any) => Promise<U> | U ): Promise<U>;
    static resolve<T>(thenable?: Promise<T> | T): Promise<T>;
    static reject(error: any): Promise<any>;
    static all<T>(promises: Array<Promise<T>>): Promise<Array<T>>;
    static race<T>(promises: Array<Promise<T>>): Promise<T>;
  }
}

The problem is that I have no way to declare that 'bluebird' is 'Promise', with typescript I would do :

export = Promise;

is there a way to declare such behavior ?

[avikchaudhuri]

Not yet, will fix.

[ptmt]

+1.

Would be nice to be able to export not only class, but function and var too:

declare module 'some-module' {
   declare var typeOfModule : string;
}

[ransanjeev]

What's the workaround for this?
I am trying to use the var ClassNames = require('classnames') ;
Not sure how to declar the interface for this.

[samwgoldman]

Generally you should be able to use the "special" identifier exports to declare your default exports. However, it seems there is an issue (#457) with polymorphic default exports which will prevent a default exported bluebird Promise class from correctly type checking.

See #455 for an example of the exports declaration.

[mroch]

ok, #457 is fixed, so this should be possible in master, and when 0.13 is released.