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Is there a combinatorial way to determine the coefficients of the universal finite-type invariant on a given knot?

There are various (equivalent?) descriptions of a universal finite-type knot invariant, e.g. https://arxiv.org/abs/q-alg/9603010. They take the form of formal power series valued in Feynman diagrams (...
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0answers
17 views

Pseudocoherent analogue of compact + nuclear = dualizable?

$\DeclareMathOperator\RHom{RHom}\DeclareMathOperator\Map{Map}\DeclareMathOperator\id{id}\DeclareMathOperator\colim{colim}$Let $(\mathcal A,\mathcal M)$ be a (normalized) analytic ring defined in ...
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0answers
14 views

Table of common relative entropies?

Does anyone know where I can find a table of relative entropies between common distributions? I don't have an immediate application in mind, but I feel like this is a piece of reference material that ...
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0answers
23 views

Norm $-1$ elements of quaternion algebras and Shimura curves

Let $Qa$ be an indefinite quaternion algebra over $\mathbb{Q}$. Let $O$ be an order of $Qa$. The moduli space of abelian surfaces with quaternionic multiplication by $O$ is usually designed as the ...
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0answers
42 views

Banach–Mazur game and mappings

The Banach-Mazur game on a nonempty space $X$ is defined as follows: two players, $I$ and $II$, alternately choose nonempty open sets \begin{matrix} I & U_0 && U_1 && \cdots ...
5
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0answers
40 views

Group extensions with non-abelian kernel

If $N$ is a normal subgroup of $G$ then there is a coupling: that is, a representation of $G/N$ in $\operatorname{Out}(N)$. In that case, the extensions of $N$ by $G/N$ affording the same coupling are ...
1
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0answers
20 views

Restrictions on pointed lifts of isometries

Let $M$ be a closed Riemannian manifold and let $f$ be an isometry of $M$ that fixes a point $\ast \in M$ and acts trivially on $\Gamma := \pi_1(M,\ast)$. Then there is a unique isometry $\tilde{f}$ ...
2
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0answers
53 views

A variation of closed-subgroup theorem

$\DeclareMathOperator\SO{SO}$Recall that the closed-subgroup theorem (Wikipedia link) says that a closed subgroup of a Lie group is a Lie group. I am pretty sure that this theorem should have a "...
2
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0answers
33 views

Rings such that torsion-free/flat/projective modules are flat/projective/free

While thinking about this question (and specifically YCor's remarks), I tried to remember what can be said about rings such that every torsion-free module is free, and I could not; and such things, ...
4
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0answers
105 views

Exotic analytic triangulations of $S^5$?

I would like to understand a bit better the nature of bad triangulations of $S^5$, discussed in two Lectures of Jacob Lurie https://www.math.ias.edu/~lurie/937notes/937Lecture2.pdf http://www-math.mit....
1
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0answers
26 views

Self-dual simplicial complexes

A simplicial complex $K$ on a vertex set $[m] = \{1,...,m \}$ is self-dual if it is equal to its Alexander dual $\widehat{K}$, where $\widehat{K}$ is the simplicial complex on $[m]$ whose simplices ...
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2answers
119 views

Is $S^1$ an open subspace of a contractible space?

Is $S^1$ an open subspace of a contractible space?
3
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0answers
49 views

How to read the paper of Arthur on trace formula on general reductive groups (Reference Request)

My question is about the correct order to read the papers by Arthur on trace formula. Arthur's papers are perfectly well-written, but maybe a little too hard for me to go through easily. I would like ...
2
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0answers
29 views

Reflexive subalgebras of $B(X)$

Let $X$ be a reflexive Banach space, and let $B(X)$ denote the set of all bounded linear operators $X\to X$. Does there exist a subalgebra $A\subseteq B(X)$ with the following properties? A is unital....
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0answers
41 views

Sufficient conditions for $b\not\in I^2$ given that $b\in I$

Let $I$ be an $R$-ideal in a commutative algebra $B$ over a commutative ring $R.$ Given $b\in I$ I want to prove that $b\not \in I^2$. Are there any sufficient conditions for showing that $b\not\in I^...

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